electrodynamics:res3.39

Это старая версия документа!


q=CU

I=\frac{dq}{dt}=C\frac{dU}{dt}=PU^{\frac{3}{2}}

\frac{dU}{U^{\frac{3}{2}}}=\frac{P}{C}dt

\frac{1}{\sqrt{U}}-\frac{1}{\sqrt{U_{0}}}=\frac{P}{2C}t

\frac{1}{\sqrt{U}}=\frac{1}{\sqrt{U_{0}}}+\frac{P}{2C}t

U=U_{0}\left(1+\frac{\sqrt{U_{0}}P}{2C}t\right)^{-2}